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7a^2+a-150=0
a = 7; b = 1; c = -150;
Δ = b2-4ac
Δ = 12-4·7·(-150)
Δ = 4201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{4201}}{2*7}=\frac{-1-\sqrt{4201}}{14} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{4201}}{2*7}=\frac{-1+\sqrt{4201}}{14} $
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